Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 2 - Acute Angles and Right Triangles - Section 2.2 Trigonometric Functions of Non-Acute Angles - 2.2 Exercises: 45

Answer

$\sin$$^{2}$ 120$^{\circ}$ + $\cos$$^{2}$ 120$^{\circ}$ = 1

Work Step by Step

$\sin$$^{2}$ 120$^{\circ}$ + $\cos$$^{2}$ 120$^{\circ}$ $\sin$$^{2}$ 120$^{\circ}$ = $\frac{\sqrt3}{2}$ $\cos$$^{2}$ 120$^{\circ}$ = -$\frac{1}{2}$ Therefore: = ($\frac{\sqrt3}{2}$)$^{2}$ + ($\frac{1}{2}$)$^{2}$ = ($\frac{3}{4}$) + ($\frac{1}{4}$) = 1 $\sin$$^{2}$ 120$^{\circ}$ + $\cos$$^{2}$ 120$^{\circ}$ = 1
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