## Trigonometry (10th Edition)

Published by Pearson

# Chapter 2 - Acute Angles and Right Triangles - Section 2.2 Trigonometric Functions of Non-Acute Angles - 2.2 Exercises: 45

#### Answer

$\sin$$^{2} 120^{\circ} + \cos$$^{2}$ 120$^{\circ}$ = 1

#### Work Step by Step

$\sin$$^{2} 120^{\circ} + \cos$$^{2}$ 120$^{\circ}$ $\sin$$^{2} 120^{\circ} = \frac{\sqrt3}{2} \cos$$^{2}$ 120$^{\circ}$ = -$\frac{1}{2}$ Therefore: = ($\frac{\sqrt3}{2}$)$^{2}$ + ($\frac{1}{2}$)$^{2}$ = ($\frac{3}{4}$) + ($\frac{1}{4}$) = 1 $\sin$$^{2} 120^{\circ} + \cos$$^{2}$ 120$^{\circ}$ = 1

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