Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 2 - Acute Angles and Right Triangles - Section 2.2 Trigonometric Functions of Non-Acute Angles - 2.2 Exercises: 40

Answer

$\tan$ -1020$^{\circ}$ = $\sqrt3$

Work Step by Step

$\cos$ -1020$^{\circ}$ First, lets find the coterminal angle. -1020$^{\circ}$ - 3(360$^{\circ}$) = 60$^{\circ}$ Next, we find the reference angle. $\theta$$^{1}$ = 60$^{\circ}$ Since the coterminal angle is in Quadrant I, $\tan$ is negative. Therefore: $\tan$ 60$^{\circ}$ = $\sqrt3$
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