Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 2 - Acute Angles and Right Triangles - Section 2.2 Trigonometric Functions of Non-Acute Angles - 2.2 Exercises: 38

Answer

$\sin$ 1500$^{\circ}$ = $\frac{\sqrt3}{2}$

Work Step by Step

$\sin$ 1500$^{\circ}$ First, lets find the coterminal angle. 1500$^{\circ}$ - 4(360$^{\circ}$) = 60$^{\circ}$ Next, we find the reference angle. $\theta$$^{1}$ = 60$^{\circ}$ Since the coterminal angle is in Quadrant I, $\sin$ is positive. Therefore: $\sin$ 60$^{\circ}$ = $\frac{\sqrt3}{2}$
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