## Trigonometry (10th Edition)

Published by Pearson

# Chapter 2 - Acute Angles and Right Triangles - Section 2.2 Trigonometric Functions of Non-Acute Angles - 2.2 Exercises: 28

#### Answer

$sin$(1500)$^{\circ}$ = $\frac{\sqrt3}{2}$ $cos$(1500)$^{\circ}$ = $\frac{1}{2}$ $tan$(1500)$^{\circ}$ = $\sqrt3$ $cot$(1500)$^{\circ}$ = $\frac{\sqrt3}{3}$ $csc$(1500)$^{\circ}$ = $\frac{2\sqrt3}{3}$ $sec$(1500)$^{\circ}$ = 2

#### Work Step by Step

1500$^{\circ}$ We can solve for the functions by using the coterminal angle. We can find the coterminal angle by adding or subtracting 360$^{\circ}$ as many times as needed. 1500$^{\circ}$ - 360$^{\circ}$ = 1140$^{\circ}$ 1140$^{\circ}$ - 360$^{\circ}$ = 780$^{\circ}$ 780$^{\circ}$ - 360$^{\circ}$ = 420$^{\circ}$ 420$^{\circ}$ - 360$^{\circ}$ = 60$^{\circ}$ $sin$(60)$^{\circ}$ = $\frac{\sqrt3}{2}$ $cos$(60)$^{\circ}$ = $\frac{1}{2}$ $tan$(60)$^{\circ}$ = $\frac{\sqrt3}{1}$ = $\sqrt3$ $cot$(60)$^{\circ}$ = $\frac{1}{\sqrt3}$ = $\frac{\sqrt3}{3}$ $csc$(60)$^{\circ}$ = $\frac{2}{\sqrt3}$ = $\frac{2\sqrt3}{3}$ $sec$(60)$^{\circ}$ = $\frac{2}{1}$ = 2

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