Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 2 - Acute Angles and Right Triangles - Section 2.2 Trigonometric Functions of Non-Acute Angles - 2.2 Exercises: 19

Answer

$sin$(-60) = $\frac{-\sqrt3}{2}$ $cos$(-60) = $\frac{1}{2}$ $tan$(-60) = $\frac{-\sqrt3}{1}$ $cot$(-60) = $\frac{-\sqrt3}{3}$ $sec$(-60) = $\frac{2}{1}$ = 2 $csc$(-60) = $\frac{-2\sqrt3}{3}$

Work Step by Step

300$^{\circ}$ We can solve for the functions by using the coterminal angle. We can find the coterminal angle by adding or subtracting 360$^{\circ}$ as many times as needed. 300$^{\circ}$ - 360$^{\circ}$ = -60$^{\circ}$ $sin$(-60) = $\frac{-\sqrt3}{2}$ $cos$(-60) = $\frac{1}{2}$ $tan$(-60) = $\frac{-\sqrt3}{1}$ $cot$(-60) = $\frac{-1}{\sqrt3}$ = $\frac{-\sqrt3}{3}$ $sec$(-60) = $\frac{2}{1}$ = 2 $csc$(-60) = $\frac{-2}{\sqrt3}$ = $\frac{-2\sqrt3}{3}$
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