Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 2 - Acute Angles and Right Triangles - Section 2.2 Trigonometric Functions of Non-Acute Angles - 2.2 Exercises: 18

Answer

$\tan$240^{\circ} = $\sqrt3$ $\cot$240^{\circ} = $\frac{\sqrt3}{3}$

Work Step by Step

240^{\circ} We must use the reference angle of the given angle to determine the trigonometric functions. The reference angle of $\tan$240^{\circ} = $\frac{-\sqrt3}{-1}$ = $\sqrt3$ $\cot$240^{\circ} = $\frac{-1}{-\sqrt3}$ = $\frac{1}{\sqrt3}$ = $\frac{\sqrt3}{3}$
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