Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 2 - Acute Angles and Right Triangles - Section 2.1 Trigonometric Functions of Acute Angles - 2.1 Exercises: 67

Answer

$P$ = (2$\sqrt2$, 2$\sqrt2$)

Work Step by Step

The adjacent and opposite sides give the coordinates to $P$ Adjacent Side = 2$\sqrt2$ Opposite Side = 2$\sqrt2$ Therefore: $P$ = (2$\sqrt2$, 2$\sqrt2$)
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