#### Answer

True

#### Work Step by Step

From 0$^{\circ}$ to 90$^{\circ}$, as the angle increases, so does the $sine$ of the angle.
Therefore: $\sin$50$^{\circ}$ $\gt$ $\sin$40$^{\circ}$

Published by
Pearson

ISBN 10:
0321671775

ISBN 13:
978-0-32167-177-6

True

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