Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 2 - Acute Angles and Right Triangles - Section 2.1 Trigonometric Functions of Acute Angles - 2.1 Exercises: 29

Answer

$\sec$($\theta$ + 15$^{\circ}$) = $\csc$(75$^{\circ}$ - $\theta$ )

Work Step by Step

$\sec$($\theta$ + 15$^{\circ}$) According to the Cofunction Identities $\sec$$A$ = $\csc$(90$^{\circ}$ - $A$) Therefore: $\sec$($\theta$ + 15$^{\circ}$) = $\csc$(90$^{\circ}$ - 15$^{\circ}$ - $\theta$ ) $\sec$($\theta$ + 15$^{\circ}$) = $\csc$(75$^{\circ}$ - $\theta$ )
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