## Trigonometry (10th Edition)

Published by Pearson

# Chapter 1 - Trigonometric Functions - Section 1.4 Using the Definitions of the Trigonometric Functions - 1.4 Exercises: 62

#### Answer

$\sin\theta=\frac{-3}{5}$

#### Work Step by Step

1.We get this information from the sine value $x=4$ $r=5$ 2. We can use x and r to find y (we need to remember that sign of y depends on quadrant, since it ends in quadrant IV, it must be negative) $r=\sqrt {y^{2}+x^{2}}$ $y=-\sqrt {r^{2}-x^{2}}=-\sqrt {5^{2}-4^{2}}=-\sqrt {25-16}=-\sqrt {9}=-3$ 4. Then insert values, $\sin\theta=\frac{-3}{5}$

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