Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 1 - Trigonometric Functions - Section 1.3 Trigonometric Functions - 1.3 Exercises - Page 26: 6

Answer

$\sin\theta=\frac{y}{r}=\frac{-8}{17}$ $\cos\theta=\frac{x}{r}=\frac{15}{17}$ $\tan\theta=\frac{y}{x}=\frac{-8}{15}$ $\csc\theta=\frac{r}{y}=\frac{17}{-8}$ $\sec\theta=\frac{r}{x}=\frac{17}{15}$ $\cot\theta=\frac{x}{y}=\frac{15}{-8}$

Work Step by Step

$x=15$ $y=-8$ $r=\sqrt{(-8)^{2}+(15)^{2}}=\sqrt {64+225}= 17$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.