Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 1 - Trigonometric Functions - Section 1.3 Trigonometric Functions - 1.3 Exercises - Page 26: 49

Answer

$\sin\theta=\frac{y}{r}=\frac{-4}{\sqrt {65}}=\frac{-4\sqrt {65}}{65}$ $\cos\theta=\frac{x}{r}=\frac{-7}{\sqrt {65}}=\frac{-7\sqrt {65}}{65}$ $\tan\theta=\frac{y}{x}=\frac{-4}{-7}=\frac{4}{7}$ $\csc\theta=\frac{1}{\sin\theta}=-\frac{\sqrt {65}}{4}$ $\sec\theta=\frac{1}{\cos\theta}=-\frac{\sqrt {65}}{7}$ $\cot\theta=\frac{1}{\tan\theta}=\frac{7}{4}$

Work Step by Step

$x=-7$ $y=-4$ $r=\sqrt {(-7)^{2}+(-4)^{2}}=\sqrt {16+49}=\sqrt {65}$
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