Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 1 - Trigonometric Functions - Section 1.3 Trigonometric Functions - 1.3 Exercises - Page 26: 4

Answer

$\sin\theta=\frac{y}{r}=\frac{-3}{5}$ $\cos\theta=\frac{x}{r}=\frac{-4}{5}$ $\tan\theta=\frac{y}{x}=\frac{-3}{-4}$ $\csc\theta=\frac{r}{y}=\frac{5}{-3}$ $\sec\theta=\frac{r}{x}=\frac{5}{-4}$ $\cot\theta=\frac{x}{y}=\frac{-4}{-3}$

Work Step by Step

$x=-4$ $y=-3$ $r=\sqrt{(-3)^{2}+(-4)^{2}}=\sqrt {9+16}= 5$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.