## Trigonometry (10th Edition)

All angles are 60$^{\circ}$
1. Internal angles of a triangle have a sum of 180° $(2x+16)^{\circ}+(3x-6)^{\circ}+(5x-50)^{\circ}=180^{\circ}$ 2. Solve the equation for x $2x+3x+5x= 180-16+6+50$ $10x=220$ $x=22$ 3. Find angles by replacing x=22 $2(22)+16=60^{\circ}$ $3(22)-6=60^{\circ}$ $5(22)-50=60^{\circ}$