Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 1 - Trigonometric Functions - Section 1.1 Angles - 1.1 Exercises - Page 9: 124

Answer

$4$.

Work Step by Step

Using the Pythagorean theorem: $r=\sqrt{ a^{2}+b^{2}}$, here: $r=\sqrt{ ({-2\sqrt{2}})^{2}+{(2\sqrt{2}})^{2}}=\sqrt{8+8}=\sqrt{16}=4$.
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