Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 1 - Review Exercises - Page 43: 48

Answer

50 sec/year

Work Step by Step

1. Find the deg/year $\frac{360^{\circ}}{26000year}=\frac{9}{650}$ deg/year 2. Convert deg/year to min/year by multiplying by 60 $\frac{9}{650}\times 60= \frac{54}{65}$ 3. Convert min/year to sec/year by multiplying by 60 $\frac{54}{65}\times 60=\frac{648}{13} \approx 50$
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