Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 1 - Review Exercises: 36

Answer

$\sin\theta=\frac{y}{r}=\frac{5}{\sqrt {26}}=\frac{5\sqrt {26}}{26}$ $\cos\theta=\frac{x}{r}=\frac{-1}{\sqrt {26}}=-\frac{\sqrt {26}}{26}$ $\csc\theta=\frac{r}{y}=\frac{\sqrt {26}}{5}$ $\sec\theta=\frac{r}{x}=\frac{\sqrt {26}}{-1}=-\sqrt {26}$ $\tan\theta=\frac{y}{x}=\frac{5}{-1}=-5$ $\cot\theta=\frac{x}{y}=\frac{-1}{5}$

Work Step by Step

Using point (-1;5) $x= -1; y=5$ $r=\sqrt {(x)^{2}+(y)^{2}}= \sqrt {(-1)^{2}+(5)^{2}}=\sqrt {26}=\sqrt {26}$
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