## Trigonometry (10th Edition)

Published by Pearson

# Chapter 1 - Review Exercises: 34

#### Answer

$\sin\theta=\frac{y}{r}=\frac{5}{\sqrt {34}}=\frac{5\sqrt {34}}{34}$ $\cos\theta=\frac{x}{r}=\frac{3}{\sqrt {34}}=\frac{3\sqrt {34}}{34}$ $\csc\theta=\frac{r}{y}=\frac{\sqrt {34}}{5}$ $\sec\theta=\frac{r}{x}=\frac{\sqrt {34}}{3}$ $\tan\theta=\frac{y}{x}=\frac{5}{3}$ $\cot\theta=\frac{x}{y}=\frac{3}{5}$

#### Work Step by Step

1. Terminal side of the angle defined by 5x-3y=0; a point this coterminal side can be (3,5), which satisfies the equation. 2. $x= 3; y=5$ $r=\sqrt {(x)^{2}+(y)^{2}}= \sqrt {(3)^{2}+(5)^{2}}=\sqrt {34}$

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