Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 1 - Review Exercises: 30

Answer

$\sin\theta=\frac{y}{r}=\frac{-5}{\sqrt {26}}=-\frac{5\sqrt {26}}{26}$ $\cos\theta=\frac{x}{r}=\frac{1}{\sqrt {26}}=\frac{\sqrt {26}}{26}$ $\csc\theta=\frac{r}{y}=\frac{\sqrt {26}}{-5}=-\frac{\sqrt {26}}{5}$ $\sec\theta=\frac{r}{x}=\frac{\sqrt {26}}{1}=\sqrt {26}$ $\tan\theta=\frac{y}{x}=\frac{-5}{1}=-5$ $\cot\theta=\frac{x}{y}=\frac{1}{-5}=-\frac{1}{5}$

Work Step by Step

x=1; y=-5 $r=\sqrt {x^{2}+y^{2}}=\sqrt {(1)^{2}+(-5)^{2}}=\sqrt {26}$
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