Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 1 - Review Exercises: 29

Answer

$\sin180^{\circ}=\frac{y}{r}=\frac{15}{17}$ $\cos180^{\circ}=\frac{x}{r}=\frac{-8}{17}$ $\csc180^{\circ}=\frac{r}{y}=\frac{17}{15}$ $\sec180^{\circ}=\frac{r}{x}=\frac{17}{-8}$ $\tan180^{\circ}=\frac{y}{x}=\frac{15}{-8}$ $\cot180^{\circ}=\frac{x}{y}=\frac{-8}{15}$

Work Step by Step

x=-8; y=15 $r=\sqrt {x^{2}+y^{2}}=\sqrt {(-8)^{2}+(15)^{2}}=\sqrt {289}=17$
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