Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 1 - Review Exercises: 28

Answer

$\sin\theta=\frac{y}{r}=\frac{-2}{\sqrt {85}}=-\frac{2\sqrt {85}}{85}$ $\cos\theta=\frac{x}{r}=\frac{9}{\sqrt {85}}=\frac{9\sqrt {85}}{85}$ $\csc\theta=\frac{r}{y}=\frac{\sqrt {85}}{-2}=-\frac{\sqrt {85}}{2}$ $\sec\theta=\frac{r}{x}=\frac{\sqrt {85}}{9}$ $\tan\theta=\frac{y}{x}=\frac{-2}{9}$ $\cot\theta=\frac{x}{y}=\frac{9}{-2}=-\frac{9}{2}$

Work Step by Step

x=9; y=-2 $r=\sqrt {x^{2}+y^{2}}=\sqrt {(9)^{2}+(-2)^{2}}=\sqrt {85}$
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