Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 1 - Review Exercises - Page 42: 25

Answer

$\sin\theta=\frac{y}{r}=\frac{-\sqrt 3}{2}$ $\cos\theta=\frac{x}{r}=\frac{1}{2}$ $\csc\theta=\frac{r}{y}=\frac{2}{-\sqrt 3}=-\frac{2\sqrt 3}{3}$ $\sec\theta=\frac{r}{x}=\frac{2}{1}= 2$ $\tan\theta=\frac{y}{x}=\frac{-\sqrt 3}{1}=-\sqrt 3$ $\\cot\theta=\frac{x}{y}=\frac{1}{-\sqrt 3}=-\frac{\sqrt 3}{3}$

Work Step by Step

$y=\sqrt 3; x=1$ $r=\sqrt {x^{2}+y^{2}}=\sqrt {(-\sqrt 3)^{2}+(1)^{2}}=\sqrt {4}=2$
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