Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 1 - Review Exercises: 15

Answer

0.25 km

Work Step by Step

1. Corresponding sides of familiar triangles are proportional $\frac{PQ}{BA}=\frac{PC}{AC}$ 2. Substitute the values solve for BA: $\frac{1.25mm}{BA}=\frac{150km}{30km}$ $BA=\frac{1.25\times 30}{150}=0.25km$
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