## Trigonometry (10th Edition)

1. Corresponding sides of familiar triangles are proportional $\frac{PQ}{BA}=\frac{PC}{AC}$ 2. Substitute the values solve for BA: $\frac{1.25mm}{BA}=\frac{150km}{30km}$ $BA=\frac{1.25\times 30}{150}=0.25km$