The Basic Practice of Statistics 7th Edition

Published by W. H. Freeman
ISBN 10: 146414253X
ISBN 13: 978-1-46414-253-6

Chapter 7 - Exploring Data: Part I Review - Supplementary Exercises - Page 195: 7.40c

Answer

Based on the shape of the distribution, it seems reasonable to use mean and standard deviation to describe the center and the spread. Mean = $ \frac{290+420+....+580}{48} = 563.125$ Standard Deviation = $\frac{\sqrt (290-563.125)^{2} + ...... + (580-563.125)^{2}}{48-1}$ Standard Deviation = 136.5246

Work Step by Step

Based on the shape of the distribution, it seems reasonable to use mean and standard deviation to describe the center and the spread. Mean = $ \frac{290+420+....+580}{48} = 563.125$ Standard Deviation = $\frac{\sqrt (290-563.125)^{2} + ...... + (580-563.125)^{2}}{48-1}$ Standard Deviation = 136.5246
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