Answer
Based on the shape of the distribution, it seems reasonable to use mean and standard deviation to describe the center and the spread.
Mean = $ \frac{290+420+....+580}{48} = 563.125$
Standard Deviation = $\frac{\sqrt (290-563.125)^{2} + ...... + (580-563.125)^{2}}{48-1}$
Standard Deviation = 136.5246
Work Step by Step
Based on the shape of the distribution, it seems reasonable to use mean and standard deviation to describe the center and the spread.
Mean = $ \frac{290+420+....+580}{48} = 563.125$
Standard Deviation = $\frac{\sqrt (290-563.125)^{2} + ...... + (580-563.125)^{2}}{48-1}$
Standard Deviation = 136.5246