Answer
(c) $0.0951=9.51\%$
Work Step by Step
(c) Using $N(20.9,5.4)$ for $x=28$, we can find:
$z=\frac{28-20.9}{5.4}\approx1.3148$
and the area above this value can be found as:
$1 – 0.9049 =0.0951=9.51\%$
The Basic Practice of Statistics 7th Edition
by Moore, David S.; Notz, William I.; Fligner, Michael A.
Published by
W. H. Freeman
ISBN 10:
146414253X
ISBN 13:
978-1-46414-253-6
Chapter 3 - The Normal Distributions - Chapter 3 Exercises - Page 98: 3.47c
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