The Basic Practice of Statistics 7th Edition

Published by W. H. Freeman
ISBN 10: 146414253X
ISBN 13: 978-1-46414-253-6

Chapter 3 - The Normal Distributions - Chapter 3 Exercises - Page 98: 3.47a

Answer

(a) $0.0949=9.49\%$

Work Step by Step

(a) Based on the given conditions, $N=1799243$ (total) and $n= 170777$ (for scores higher than 28), thus $P(x\gt28)=\frac{170777}{1799243}\approx0.0949=9.49\%$
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