The Basic Practice of Statistics 7th Edition

Published by W. H. Freeman
ISBN 10: 146414253X
ISBN 13: 978-1-46414-253-6

Chapter 3 - The Normal Distributions - Chapter 3 Exercises - Page 97: 3.44

Answer

mean = 250, standard deviation = 175.78

Work Step by Step

If a manager gets an "A" grade, they are in the top 10%. Another way of saying this is that they have a normal value of .9. If a manager gets a "C" grade, they are in the bottom 10%. Another way of saying this is that they have a normal value of .1. The formula for a manager with an "A" grade: $(475-mean)/deviation = 1.28$ The formula for a manager with a "C" grade: $(25-mean)/deviation = -1.28$ $(475-mean)/deviation = 1.28$ $(25-mean)/deviation = -1.28$ $(475-mean)/deviation = 1.28$ $-1*(25-mean)/deviation = -1*-1.28$ $(475-mean)/deviation = 1.28$ $(-25+mean)/deviation = 1.28$ $(475-mean)/deviation = (-25+mean)/deviation$ $475 - mean = mean - 25$ $475 - mean + mean + 25 = mean - 25 + mean + 25$ $500 = 2 * mean$ $mean = 250$ $(475-mean)/deviation = 1.28$ $(475-250)/deviation = 1.28$ $225/deviation = 1.28$ $225/deviation * deviation= 1.28* deviation$ $225 = 1.28 * deviation$ $225/1.28 = deviation$ $175.78 = deviation$
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