The Basic Practice of Statistics 7th Edition

Published by W. H. Freeman
ISBN 10: 146414253X
ISBN 13: 978-1-46414-253-6

Chapter 3 - The Normal Distributions - Chapter 3 Exercises - Page 96: 3.32a

Answer

.66%

Work Step by Step

$(135-104)/12.5 = z$ $31/12.5 = z$ $2.48= z$ .9934 is the value for a z-value of 2.48 $1-.9934 = .0066$
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