Answer
See below.
Work Step by Step
The degree of freedom of the numerator is the number of groups minus 1: $dfn=I-1=3-1=2.$
The degree of freedom of the denominator is the total sample size($N$) minus the number of groups: $dfd=N-I=(244+734+364)-3=1339$
If the P-value is less than $\alpha$, which is the significance level, then this means the rejection of the null hypothesis and that the test is statistically significant.
$P\lt 0.05$, thus we reject the null hypothesis. Thus there is sufficient evidence to support the claim that the sample means in the tree groups differ.
