Answer
$(0.1178,0.1467)$
Work Step by Step
The degree of freedom is the sample size minus $2$: $df=n-2=37-2=35\gt30$.
The critical value is given in the row $df=30$ and in the column with $c=0.95$ of the table. Thus $t=2.042$.
The confidence interval is then: $b\pm tSE_b=0.132259\pm2.042\cdot0.007067$, thus the confidence interval is: $(0.1178,0.1467)$
