Answer
(b).
Work Step by Step
The critical value is given in the row $df=n-1=135-1=134\gt1000$ and in the column with $c=0.95$ of the table. Thus $t_{\alpha/2}=1.984$.
Thus the confidence interval is: $\overline{x}\pm t_{\alpha/2}\frac{s}{\sqrt n}$, which here is: $2.33\pm1.984\frac{1}{\sqrt{135}}=2.33\pm0.17$ Thus the answer is (b).