Answer
$(0.3754,0.4252)$,
Work Step by Step
$\hat{p}=\frac{x}{n}=\frac{594}{1484}\approx0.4003$
The z-value belonging to the $95\%$ confidence interval according to the table is $z=1.96$, thus the confidence interval is: $\hat{p}\pm z\sqrt{\frac{p(1-p)}{n}}$, which here is: $0.4003\pm 1.96\sqrt{\frac{0.4003\cdot(1-0.4003)}{1484}}$, thus the confidence interval is $(0.3754,0.4252)$,