Answer
Yes.
Work Step by Step
The margin of error is: $z\sqrt{\frac{p(1-p)}{n}}$, thus it depends on $p$, which varies in each state, thus the margin of error will also vary.
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.