Answer
See below.
Work Step by Step
$np=1500\cdot0.9=1350\gt10$, $n(1-p)=1500\cdot0.1=150\gt10$, thus the sampling distribution of $\hat{p}$ is approximately normal with a mean of $p=0.9$ and a standard deviation of $\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.9\cdot0.1}{1500}}\approx0.0039$
