Answer
With Outliers:
Here we have n = 9, x̅ = 0.549, s = 0.403, df = 8 and Confidence Level = 90%
Using Table C of the book we have t = 1.860
$s_{x̅} = \frac{0.403}{\sqrt 9} = 0.134$
Lower Bound = 0.549 - (1.860)(0.134) = 0.30
Upper Bound = 0.549 + (1.860)(0.134) = 0.798
Without Outliers:
Here we have n = 7, x̅ = 0.3486, s = 0.0527, df = 6 and Confidence Level = 90%
Using Table C of the book we have t = 1.943
$s_{x̅} = \frac{0.0527}{\sqrt 7} = 0.02$
Lower Bound = 0.3486 - (1.943)(0.02) = 0.31
Upper Bound = 0.3486 + (1.943)(0.02) = 0.387
Work Step by Step
Use stats menu of minitab to calculate mean and stdev.
