Answer
From answer 11, we have n = 16, x̅ = 0.1012, s = 0.2263, df = 15
For a 99% confidence level, using Table C we have:
t = 2.947
$σ_{x̅} = \frac{σ}{\sqrt n} = \frac{0.2263}{\sqrt 16} = 0.0566$
Lower Bound = 0.1012 - (2.947)(0.0566) = 0.0655
Upper Bound = 0.1012 + (2.947)(0.0566) = 0.268
Work Step by Step
Given above
