Answer
(c) 0.023
Work Step by Step
We find:
P(shot) = 0.4
P(Misses first two shots) $= (0.6)^{2} = 0.36$
P(Makes other three shots) $=(0.4)^{3} = 0.064$
P(Misses first two shots and makes other three) = 0.36 x 0.064 = 0.023
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