The Basic Practice of Statistics 7th Edition

Published by W. H. Freeman
ISBN 10: 146414253X
ISBN 13: 978-1-46414-253-6

Chapter 19 - From Data Production to Inference: Part III Review - Supplementary Exercises - Page 451: 19.55b

Answer

Here, we have n = 20, σ = 0.7 Using the four step process for the significance test: PLAN: μ = 98.6, $H_{o}: μ = 98.6$, $H_{a}: μ \ne 98.6$ SOLVE: For x̅ = 98.203 $z = \frac{98.203 - 98.6}{0.7/\sqrt 20} = -2.536 \approx -2.54$ Using Table A of the book, we have: P(z < -2.54 or z > 2.54) = 2P(z < -2.54) = 2(0.0055) = 0.0110 CONCLUDE: since p < 0.05, we reject the Null hypothesis that mean body temperature is equal to 98.6

Work Step by Step

Here, we have n = 20, σ = 0.7 Using the four step process for the significance test: PLAN: μ = 98.6, $H_{o}: μ = 98.6$, $H_{a}: μ \ne 98.6$ SOLVE: For x̅ = 98.203 $z = \frac{98.203 - 98.6}{0.7/\sqrt 20} = -2.536 \approx -2.54$ Using Table A of the book, we have: P(z < -2.54 or z > 2.54) = 2P(z < -2.54) = 2(0.0055) = 0.0110 CONCLUDE: since p < 0.05, we reject the Null hypothesis that mean body temperature is equal to 98.6
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