The Basic Practice of Statistics 7th Edition

Published by W. H. Freeman
ISBN 10: 146414253X
ISBN 13: 978-1-46414-253-6

Chapter 18 - Inference in Practice - Chapter 18 Exercises - Page 436: 18.43

Answer

$97$

Work Step by Step

$n=(\frac{z_{\alpha/2}\sigma}{E})^2$ (we have to round up) $1-\alpha=0.95$, thus according to the table, $z_{\alpha/2}=z_{0.025}=1.96$. $n=(\frac{1.96\cdot3000}{600})^2=96.04\approx97$
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