The Basic Practice of Statistics 7th Edition

Published by W. H. Freeman
ISBN 10: 146414253X
ISBN 13: 978-1-46414-253-6

Chapter 18 - Inference in Practice - Chapter 18 Exercises - Page 436: 18.42

Answer

$32491$

Work Step by Step

$n=(\frac{z_{\alpha/2}\sigma}{E})^2$ (we have to round up) $1-\alpha=0.99$, thus according to the table, $z_{\alpha/2}=z_{0.005}=2.575$. $n=(\frac{2.575\cdot7}{0.1})^2=32490.06\approx32491$
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