The Basic Practice of Statistics 7th Edition

Published by W. H. Freeman
ISBN 10: 146414253X
ISBN 13: 978-1-46414-253-6

Chapter 17 - Tests of Significance: The Basics - Chapter 17 Exercises - Page 413: 17.41

Answer

There is sufficient evidence to support the claim that there is a loss, on average, in bone mineral with nursing mothers.

Work Step by Step

Mean = $\frac{-4.7 - 2.5 - 4.9 + ... + .2 -2.2 -5.1}{47}$ = -3.5872 z = $\frac{x-u}{o/\sqrt n}$ = $\frac{-3.5872 - 0}{2.5/\sqrt 47}$ = -9.84 P = P(Z < -9.84) = 0
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