The Basic Practice of Statistics 7th Edition

Published by W. H. Freeman
ISBN 10: 146414253X
ISBN 13: 978-1-46414-253-6

Chapter 14 - Binomial Distributions - Chapter 14 Exercises - Page 342: 14.33b

Answer

$412.68,16.4548$

Work Step by Step

The mean of a binomial distribution: $\mu=np=1200\cdot0.3439=412.68$ The standard deviation of a binomial distribution: $\sigma=\sqrt{npq}=\sqrt{np(1-p)}=\sqrt{1200\cdot0.3439\cdot(1-0.3439)}=16.4548$
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