Answer
Option (b) is correct answer
Work Step by Step
$P(0/3 wins) = P(lose first and lose second and lose third)
\\
= P(lose first play)^{3}
\\
= (1 - P(win first play))^{3}
\\
= (1 - 0.02)^{3}
= (0.98)^{3}\\
= 0.941$
The Basic Practice of Statistics 7th Edition
by Moore, David S.; Notz, William I.; Fligner, Michael A.
Published by
W. H. Freeman
ISBN 10:
146414253X
ISBN 13:
978-1-46414-253-6
Chapter 13 - General Rules of Probability - Check Your Skills - Page 320: 13.17
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