The Basic Practice of Statistics 7th Edition

Published by W. H. Freeman
ISBN 10: 146414253X
ISBN 13: 978-1-46414-253-6

Chapter 13 - General Rules of Probability - Chapter 13 Exercises - Page 323: 13.47a

Answer

Total no. of possible outcomes = 36 Possible doubles = {(1,1), (2,2), (3,3), (4,4), (5,5), (6,6)} Hence, P(Doubles) = 6/36 = 1/6

Work Step by Step

Total no. of possible outcomes = 36 Possible doubles = {(1,1), (2,2), (3,3), (4,4), (5,5), (6,6)} Hence, P(Doubles) = 6/36 = 1/6
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