Answer
$H_0: \mu=48$
$H_1: \mu \gt 48$
Test Statistic: $1.070$
Critical value: $1.833$
We fail to reject the null hypothesis, for the value of P is greater than .1. Thus, we cannot conclude that there are more than 48 words on a page.
Work Step by Step
We want to see if the mean change is greater than 48, so we know $H_0: \mu = 48$ and $H_1: \mu>48$. We now use a Ti-84 calculator. To solve, go to "Stat," then "Tests," and then select "Stats." Next, plug in 48 for $\mu_0$, 53.3 in for $\bar{x}$, 15.7 for $Sx$, and 10 for n. Then, select "$>\mu_0$" and push calculate. Doing this, we find that the test statistic, t, is 1.070 and that the critical value is 1.833. From this, we can find that $P>.1$, so we cannot reject the null hypothesis.
