Essentials of Statistics (5th Edition)

Published by Pearson
ISBN 10: 0-32192-459-2
ISBN 13: 978-0-32192-459-9

Chapter 6 - Normal Probability Distributions - 6-5 The Central Limit Theorem - Page 288: 15

Answer

a. 140 b. 9999 c. .8078 d. No

Work Step by Step

a. We find that the mean weight is: $=\frac{3500}{25}=140\ Ibs$ b. We find that the z-score is: $z = \frac{(140)-(182.9)}{40.8/(\sqrt{25})}=-5.257$ This is greater than -3.5, so it follows that the probability is .9999. c. We find the z score: $z=\frac{175-182.9}{40.8/\sqrt{20}}=-.87$ Consulting the table of z-scores, we see that the probability is .8078. d. No, this is still not safe. You want a much higher probability for safety regulations.
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