Essentials of Statistics (5th Edition)

Published by Pearson
ISBN 10: 0-32192-459-2
ISBN 13: 978-0-32192-459-9

Chapter 6 - Normal Probability Distributions - 6-3 Applications of Normal Distributions - Page 264: 34

Answer

a) Mean: .78 Standard Deviation: .0044 b) Min: .77 Max: .795

Work Step by Step

a) We know that the mean is equal to the sum of all of the data points divided by the number of data points. Doing this, we find that the mean is .78. In addition, using the standard deviation function in Microsoft Excel, we find that the standard deviation is .004. b) We use the z-score of $\pm3.4$ to find: $max=(3.4)(.0044)+.78=.795$ $min=(-3.4)(.0044)+.78=.77$
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