Essentials of Statistics (5th Edition)

Published by Pearson
ISBN 10: 0-32192-459-2
ISBN 13: 978-0-32192-459-9

Chapter 6 - Normal Probability Distributions - 6-3 Applications of Normal Distributions - Page 264: 30

Answer

16.73

Work Step by Step

By using the table, the z-score corresponding to 0.99: z=2.33. Hence the corresponding value:$mean+z⋅standard \ deviation=14.4+2.33⋅1=16.73.$
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