Essentials of Statistics (5th Edition)

Published by Pearson
ISBN 10: 0-32192-459-2
ISBN 13: 978-0-32192-459-9

Chapter 5 - Discrete Probability Distributions - Review - Cumulative Review Exercises - Page 232: 3

Answer

a) .282 b) .303 c) .242 d) .297 e) .0792 f) .738 g) .703

Work Step by Step

a) We use the equation for probability to find: $P=\frac{number\ of\ desired\ outcomes}{total\ number\ of\ outcomes}$ $P = \frac{121+51}{611}=.282$ b) We use the equation for probability to find: $P=\frac{number\ of\ desired\ outcomes}{total\ number\ of\ outcomes}$ $P = \frac{121}{121+279}=.303$ c) We use the equation for probability to find: $P=\frac{number\ of\ desired\ outcomes}{total\ number\ of\ outcomes}$ $P = \frac{51}{160+51}=.242$ d) We use the equation for probability to find: $P=\frac{number\ of\ desired\ outcomes}{total\ number\ of\ outcomes}$ $P = \frac{51}{121+51}=..297$ e) We use the result from part a to find: $P=.282^2=.0792$ f) We use the results above to find: $=\frac{400}{611}+\frac{51}{611}=.738$ g) We use the equation for probability to find: $P=\frac{number\ of\ desired\ outcomes}{total\ number\ of\ outcomes}$ $P = \frac{121}{121+51}=.703$
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