Essentials of Statistics (5th Edition)

Published by Pearson
ISBN 10: 0-32192-459-2
ISBN 13: 978-0-32192-459-9

Chapter 5 - Discrete Probability Distributions - 5-3 Binomial Probability Distributions - Page 222: 44

Answer

0.978, about 97.8% of the shipments will be accepted and about 2.2% will be rejected.

Work Step by Step

P(accepted)=$P(X=0)+P(X=1)+P(X=2)={30\choose 0} \cdot (0.98)^{30}\cdot (0.02)^0+{30\choose 1} \cdot (0.98)^{29}\cdot (0.02)^1+{30\choose 2} \cdot (0.98)^{28}\cdot (0.02)^2=0.545+0.334+0.099=0.978$. About 97.8% of the shipments will be accepted and about 2.2% will be rejected.
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